Why does the momentum of an object affect the force of impact?

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Momentum affects the force of impact due to differences in elasticity and mass between objects. When a soccer ball is kicked, it deforms and absorbs some of the impact energy, resulting in less force felt by the foot. In contrast, a rock is less elastic and does not deform, leading to a quicker transfer of force and more pain upon impact. The mass of the objects also plays a significant role, as a heavier rock exerts more force compared to a lighter soccer ball. Understanding these factors clarifies why impacts vary in sensation and injury potential.
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A question about momentum ??

I have a question about momentum with respect to Newtons Second Law of Motion.When We hit a soccer ball our foot does not hurt but when we hit a rock our foot hurts badly.What is the reason of this ? I think it is related to reaction time
 
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Yup, if you view a soccer ball being kicked in slow-motion, you will actually see it deform as it is elastic. The rock however, is much less elastic and hence the period of the interaction is significantly less.
 


The mass of the two objects would also play a part as well. Compare the mass of a soccer ball to a "rock".
 
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
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