Why does the normal force affect friction?

AI Thread Summary
The discussion revolves around the relationship between normal force and static friction, specifically the equation Fstatic friction = μsFnormal. The normal force is described as the force exerted by a surface that affects how much the surfaces interact, with increased normal force leading to greater friction due to more surface irregularities engaging. Participants suggest that friction can also be understood at a molecular level, where increased downward force makes it harder for surfaces to slide past each other. The conversation highlights that while the roughness model is common, it is not the sole explanation for friction. Overall, understanding the connection between normal force and friction is essential for teaching static friction effectively.
jumbogala
Messages
414
Reaction score
4

Homework Statement


I am student teaching a class about static friction soon.

I am worried a student is going to ask me where Fstatic friction = μ
sFnormal comes from. I am not sure how to explain it.

Homework Equations





The Attempt at a Solution


I've always thought of it this way. Consider a rock on a table. Normal force is a measure of how hard the table pushes up on the rock.

If the normal force pushes harder, the rough surface irregularities on the table "catch" more on the rock and that increases friction.

But it just occurred to me that I have NO clue if this is true. Can anyone help me out?
 
Physics news on Phys.org
Teach friction empirically and students will discover that it is proportional to the weight of the object.

It is commonly taught that friction comes from irregularities in the surfaces that catch on each other - but that is not the only source. See:
http://van.physics.illinois.edu/qa/listing.php?id=18391

If you use the "roughness" model, to slide, the surfaces have to lift slightly.
The harder you press the surfaces together, the harder it is for the surfaces to jolt apart enough to slide, thus, the more friction. The "normal force" is one way of quantifying how hard the surfaces are pressed together.
 
Well, since nobody bit, I'll try to give my two cents. I'm really just a first year student, so I may be wrong.

I think that if you think of it on the molecular level, it'll make more sense. If you visualize all little crags/valleys, you can see how, if you apply more downward force, you will need more force in the x direction to move it. It would be similar to rolling a wheel over a step.

It makes sens to me, not sure it it really works like that.

It's such an intuitive idea that I doubt you'll be asked about it, I didn't even think of this question until I read your post.
 
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
Back
Top