riseofphoenix
- 294
- 2
The two wires shown in the figure below are separated by d = 8.0 cm and carry currents of I = 4.85 A in opposite directions.
d = 8 cm = 0.08 m
d = 8 cm = 0.08 m
r = 0.08/2 = 0.04 m
2d = 21.6 cm
I (up) = 4.80 A
I (down) = 4.80 A
(a) Find the magnitude and direction of the net magnetic field at a point midway between the wires.
magnitude: ______ µT
direction: ______
(b) Find the magnitude and direction of the net magnetic field at point P1, 8.0 cm to the right of the wire on the right.
magnitude: ______ µT
direction: ______
(c) Find the magnitude and direction of the net magnetic field at point P2, 2d = 16.0 cm to the left of the wire on the left.
magnitude: ______ µT
direction: ______
_______________________________________________________________________________________________________________________
Solution:
Assume that the wire on the right is wire 1 and that on the left is wire 2. Also, choose the positive direction for the magnetic field to be out of the page and negative into the page.
(a) At the point half way between the two wires,
Bnet = -B1 - B2
Bnet = -[(µI1)2πr1 + (µI2)/2πr2]
Bnet = -(µ/2πr)(I1 + I2)
Bnet = [-(4π x 10-7)/2π(0.04 m)](4.85 + 4.85)
Bnet = (-0.000001257/0.251)(9.7)
Bnet = -0.000012193/0.251
Bnet = -4.85 x 10-5 T
or
Bnet = 48.5 µT into the page
QUESTION: the signs for B1 and B2 changed. WHY? I don't understand!
(b) At point P1,
Bnet = +B1 - B2
Bnet = (µ/2π)[(I1/r1) - (I2/r2)]
Bnet = [(4π x 10-7)/6.283][(4.85 A)/(0.08 m) - (4.85 A)/(0.16)]
Bnet = (0.0000002)(60.625 - 30.125)
Bnet = (0.0000002)(30.5)
Bnet = 0.0000061
Bnet = 6 µT out of page
QUESTION: the signs for B1 and B2 changed. WHY? I don't understand!
(c) At point P3
Bnet = -B1 + B2
Bnet = (µ/2π)[-(I1/r1) + (I2/r2)]
Bnet = [(4π x 10-7)/6.283][-(4.85 A)/(0.24 m) + (4.85 A)/(0.16)]
Bnet = (0.0000002)(-20.208 + 30.125)
Bnet = (0.0000002)(9.917)
Bnet = 0.000001983
Bnet = 1.983 µT out of page
QUESTION: the signs for B1 and B2 changed. WHY? I don't understand!
d = 8 cm = 0.08 m
d = 8 cm = 0.08 m
r = 0.08/2 = 0.04 m
2d = 21.6 cm
I (up) = 4.80 A
I (down) = 4.80 A
(a) Find the magnitude and direction of the net magnetic field at a point midway between the wires.
magnitude: ______ µT
direction: ______
(b) Find the magnitude and direction of the net magnetic field at point P1, 8.0 cm to the right of the wire on the right.
magnitude: ______ µT
direction: ______
(c) Find the magnitude and direction of the net magnetic field at point P2, 2d = 16.0 cm to the left of the wire on the left.
magnitude: ______ µT
direction: ______
_______________________________________________________________________________________________________________________
Solution:
Assume that the wire on the right is wire 1 and that on the left is wire 2. Also, choose the positive direction for the magnetic field to be out of the page and negative into the page.
(a) At the point half way between the two wires,
Bnet = -B1 - B2
Bnet = -[(µI1)2πr1 + (µI2)/2πr2]
Bnet = -(µ/2πr)(I1 + I2)
Bnet = [-(4π x 10-7)/2π(0.04 m)](4.85 + 4.85)
Bnet = (-0.000001257/0.251)(9.7)
Bnet = -0.000012193/0.251
Bnet = -4.85 x 10-5 T
or
Bnet = 48.5 µT into the page
QUESTION: the signs for B1 and B2 changed. WHY? I don't understand!
(b) At point P1,
Bnet = +B1 - B2
Bnet = (µ/2π)[(I1/r1) - (I2/r2)]
Bnet = [(4π x 10-7)/6.283][(4.85 A)/(0.08 m) - (4.85 A)/(0.16)]
Bnet = (0.0000002)(60.625 - 30.125)
Bnet = (0.0000002)(30.5)
Bnet = 0.0000061
Bnet = 6 µT out of page
QUESTION: the signs for B1 and B2 changed. WHY? I don't understand!
(c) At point P3
Bnet = -B1 + B2
Bnet = (µ/2π)[-(I1/r1) + (I2/r2)]
Bnet = [(4π x 10-7)/6.283][-(4.85 A)/(0.24 m) + (4.85 A)/(0.16)]
Bnet = (0.0000002)(-20.208 + 30.125)
Bnet = (0.0000002)(9.917)
Bnet = 0.000001983
Bnet = 1.983 µT out of page
QUESTION: the signs for B1 and B2 changed. WHY? I don't understand!