Why Does Torque Equilibrium Not Solve for Fcy in Static Equilibrium Problems?

AI Thread Summary
The discussion focuses on the challenges of solving for the force Fcy in static equilibrium problems, particularly in the context of a ladder leaning against a frictionless wall. Participants question why using torque equilibrium does not yield a solution and discuss the implications of ignoring friction along the wall while considering it along the floor. The conversation highlights the importance of normal forces and their relationship to friction, especially when a person is climbing the ladder. Additionally, there are references to textbook resources that provide similar problems for further study. Overall, the thread emphasizes the complexities of applying static equilibrium principles in practical scenarios.
Sunwoo Bae
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Homework Statement
A 5m long ladder leans against a smooth wall at a point 4m above a cement floor as shown in the figure (image below). The ladder is uniform and has mass m = 12kg. Assuming the wall is frictionless (but the floor is not), determine the forces exerted on the ladder by the floor and by the wall.
Relevant Equations
total torque = 0
problem.jpg

I have two questions regarding this problem

1. The following is my attempt to solve Fcy using the fact that the addition of torque = 0. I considered force mg and Fcy and their lever arms to set up the equilibrium. But this method seems not to work? Why?

attempt.jpg

2.At the bottom of the question, it reads, "Why is it reasonable to ignore friction along the wall, but not reasonable to ignore it along the floor?" What would be an answer to this problem?
 
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I presume you are taking torques about the point of contact with the wall in your equation. But you haven't included the torque of ##\vec{F}_{C,x}## in your equation (N.B. you also missed an "##=0##" :wink:).

Sunwoo Bae said:
2.At the bottom of the question, it reads, "Why is it reasonable to ignore friction along the wall, but not reasonable to ignore it along the floor?" What would be an answer to this problem?

Is it possible for the ladder to be in static equilibrium if there is zero friction from the floor?
 
etotheipi said:
I presume you are taking torques about the point of contact with the wall in your equation. But you haven't included the torque of ##\vec{F}_{C,x}## in your equation (N.B. you also missed an "##=0##" :wink:).
Alternatively, @Sunwoo Bae is taking moments about the base of the wall, in which case it is FW that is missing.
 
Sunwoo Bae said:
2.At the bottom of the question, it reads, "Why is it reasonable to ignore friction along the wall, but not reasonable to ignore it along the floor?" What would be an answer to this problem?
Since force of friction depends on the normal force, where will you see the biggest normal (to ground or wal) force, especially when a person is climbing that ladder and the angle of lean is moderated?
Hint: Most extension ladders have rubber pads and spikes at bottom end and nothing at top end.

parts-of-extension-ladder-1.png
 
Sunwoo Bae said:
Homework Statement: A 5m long ladder leans against a smooth wall at a point 4m above a cement floor as shown in the figure (image below). The ladder is uniform and has mass m = 12kg. Assuming the wall is frictionless (but the floor is not), determine the forces exerted on the ladder by the floor and by the wall.
Relevant Equations: total torque = 0

View attachment 267227
I have two questions regarding this problem

1. The following is my attempt to solve Fcy using the fact that the addition of torque = 0. I considered force mg and Fcy and their lever arms to set up the equilibrium. But this method seems not to work? Why?

View attachment 267228
2.At the bottom of the question, it reads, "Why is it reasonable to ignore friction along the wall, but not reasonable to ignore it along the floor?" What would be an answer to this problem?
Good day. Can I know the name of the textbook you took the image from?. Thank you
 
JoeDGreat said:
Good day. Can I know the name of the textbook you took the image from?. Thank you
Hi. Welcome to PF. It may be worth noting that the post to which you are replying is over 3 years old. You may not get a response from the OP!
 
Steve4Physics said:
Hi. Welcome to PF. It may be worth noting that the post to which you are replying is over 3 years old. You may not get a response from the OP!
Alright, thanks. I just love the explanation by the textbook.
 
JoeDGreat said:
Alright, thanks. I just love the explanation by the textbook.
That is out of "Physics for Scientists & Engineers", Giancoli. Fourth Edition has the problem ( I have the text book ), I would imagine theirs is a later version, but maybe not.
 
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