Why Ignore the Magnetic Field in a Mass Spectrometer?

AI Thread Summary
In a mass spectrometer, the electric field strength is critical for the velocity selector, which is set at 2,500 V/m, while the magnetic field strength is 0.035 T. The magnetic field is not ignored; rather, it plays a role in the calculations for the deflection chamber. The confusion arises from the distinction between the velocity selector and the deflection chamber, where the magnetic field's influence is more pronounced in the latter. The calculations for the path radius of a singly charged ion with a mass of 2.18E-26 involve both electric and magnetic fields, emphasizing their importance in the overall function of the spectrometer. Understanding the specific roles of these fields clarifies their application in mass spectrometry.
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Homework Statement



Consider a simple mass spectrometer. The magnitude of the electric field between the plates of the velocity selector is 2 500 V/m and the magnetic field in both the velocity selector and the deflection chamber has a magnitude of 0.035 T. Calculate the radius of the path for a singly charged ion with mass m=2.18E-26.




Homework Equations




qE=1/2 mv^2

F = qVxB

The Attempt at a Solution



Solution attached.

Why is the magnetic field ignored for the velocity selector portion??
 

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I don't understand what you mean by ignored as the field strength is used in both calculations.
 
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