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Why is lim x->infinity of 2^-x = 0?

  1. Nov 17, 2012 #1
    1. The problem statement, all variables and given/known data

    Hey guys, just getting into the exponential functions and got stuck on something. Can someone please explain this for me?

    Find lim x-->∞ (2^-x)

    The answer is 0

    Why? I dont quite understand.

    I know that something like 2^-x would just be 1/2^x


    2. Relevant equations

    3. The attempt at a solution
  2. jcsd
  3. Nov 17, 2012 #2


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    2^-x = 1/(2^x)

    As x tends to infinity, what happens to the denominator, (2^x)?
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