Why is lim x->infinity of 2^-x = 0?

[nukeman]

Homework Statement

Hey guys, just getting into the exponential functions and got stuck on something. Can someone please explain this for me?

Find lim x-->∞ (2^-x)

The answer is 0

Why? I don't quite understand.

I know that something like 2^-x would just be 1/2^x

?

Homework Equations

The Attempt at a Solution

 

[SteamKing]

2^-x = 1/(2^x)

As x tends to infinity, what happens to the denominator, (2^x)?