Why Is My Calculation of Electrostatic Equilibrium Incorrect?

AI Thread Summary
The discussion revolves around calculating electrostatic equilibrium involving three charges. The user initially equated the forces exerted by two charges but encountered difficulties when trying to incorporate a third charge, particularly due to unknowns in distance and charge magnitude. It was suggested to position the third charge to the left of the origin and analyze the forces acting on it. Participants emphasized the importance of understanding the forces and electric fields involved, noting that the specific value of the third charge may not be necessary for finding equilibrium. Clarifying the forces acting on each charge is crucial for resolving the user's calculation errors.
cs44167
Messages
8
Reaction score
0
Homework Statement
A charge of 2.0 microcoulombs is positioned at (0,0) and a charge of -6.0 microcoulombs is positioned at (3,0). Where must a third charge be placed in order to be in electrostatic equilibrium?
Relevant Equations
Electrostatic Force = kq1q2/d^2
I set the electrostatic force exerted by the object at (0,0) and (3,0) equal to each other, dividing out k and q2. I was left with q1/d^2 for both terms and substituted in the given charges for each object. I then replaced d^2 for the object at (0,0) with “x^2” and d^2 for the object at (3,0) with “(3-x)^2”. I got an answer of (1.098, 0) which made sense that it would be somewhere left of 1.50, but was incorrect.

Any helpers in where I went wrong? Thanks.
 
Physics news on Phys.org
In which directions do the forces go?
 
Orodruin said:
In which directions do the forces go?
So the third charge would have to be to the left of the origin, correct?

Then you would have negative-positive-negative.

From there I’m struggling with Coulomb’s Law because we don’t know the magnitude of the charge on the third object. I have q3q1/x^2 =q1q2/3^2 but we don’t know x or q3.
 
cs44167 said:
So the third charge would have to be to the left of the origin, correct?

Then you would have negative-positive-negative.

From there I’m struggling with Coulomb’s Law because we don’t know the magnitude of the charge on the third object. I have q3q1/x^2 =q1q2/3^2 but we don’t know x or q3.

Make sure to draw a diagram. Try positioning this third charge at a distance ##d## to the left of the origin, and then draw on the forces. I don't believe you need to know ##q_{3}##.
 
cs44167 said:
So the third charge would have to be to the left of the origin, correct?

Then you would have negative-positive-negative.

From there I’m struggling with Coulomb’s Law because we don’t know the magnitude of the charge on the third object. I have q3q1/x^2 =q1q2/3^2 but we don’t know x or q3.

You can look at this two ways. You can take any charge ##q_3## and try to make the total force on ##q_3## due to ##q_1## and ##q_2## equal to zero. If ##q_3## doesn't cancel out, then you have a serious conceptual or mathematical problem!

Or, you can look for a position where the electric field due to ##q_1## and ##q_2## is zero. Then, clearly, the value of ##q_3## is irrelevant.
 
cs44167 said:
I have q3q1/x^2 =q1q2/3^2 but we don’t know x or q3.
Can you write down in words what ##\frac{q_3q_1}{x^2}## is supposed to be? It is the force of object [which] on object [which other]?

Can you write down in words what ##\frac{q_3q_2}{3^2}## is supposed to be? It is the force of object [which] on object [which other]?

Which object are you trying to find the force on?
 
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
Thread 'A cylinder connected to a hanged mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top