Why Is My Calculation of Voltage Over 1.5R x R Incorrect?

  • Thread starter Thread starter faen
  • Start date Start date
  • Tags Tags
    Current
AI Thread Summary
The user is struggling with calculating voltage across resistors in a circuit involving 1.5R and R in parallel, followed by a series connection to a 0.6R resistor. They initially attempted to find the voltage across the parallel resistors and then calculate the current through R, but encountered errors. The discussion emphasizes the importance of applying Kirchhoff's voltage and current laws correctly. The user seeks clarification on their initial mistake to avoid future errors. Understanding these fundamental concepts is crucial for solving similar problems effectively.
faen
Messages
138
Reaction score
0

Homework Statement



Can somebody please explain to me what i did wrong here? Got exam tomorrow and it would probably be usefull to know.. Thx

skann0006.jpg


Homework Equations



axb = a*b/(a+b)

The Attempt at a Solution



First i tried finding the voltage over 1.5R x R.. Then divide that voltage over R to find the current over R... For some strange reason this is wrong. Plz someone help me to understand why..
 
Physics news on Phys.org
treat the 1.5R and R as parallel. then in series with the 0.6R to get the overall resistance. current going through 0.6R = voltage/overall R. Then the same current split into the 1.5R and R, calculate.
 
nice, thanks a lot. Now i got further :)

However if u would be able to point out what i assumed wrong in my first attempt itd be apreciated as well, so i don't happen to do a similar mistake again
 
hmm... its like really basic. just get familar with kirchhoffs v and i law. u'll be fine
 
Thread 'Have I solved this structural engineering equation correctly?'
Hi all, I have a structural engineering book from 1979. I am trying to follow it as best as I can. I have come to a formula that calculates the rotations in radians at the rigid joint that requires an iterative procedure. This equation comes in the form of: $$ x_i = \frac {Q_ih_i + Q_{i+1}h_{i+1}}{4K} + \frac {C}{K}x_{i-1} + \frac {C}{K}x_{i+1} $$ Where: ## Q ## is the horizontal storey shear ## h ## is the storey height ## K = (6G_i + C_i + C_{i+1}) ## ## G = \frac {I_g}{h} ## ## C...
Back
Top