Why Is Phase Velocity Defined as v=w/k?

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Phase velocity is defined as v = ω/k, where ω is the angular frequency and k is the wave number, derived from the harmonic wave equation f(x,t) = a sin(kx - ωt). By rewriting the equation as f(x,t) = a sin(k(x - (ω/k)t)), it becomes clear that if x - (ω/k)t = s (a constant), then the wave's value remains constant, represented as a sin(ks). This indicates that the signal propagates in the positive x-direction at a velocity of ω/k. The trajectory of the signal can be expressed as x = s + (ω/k)t, confirming that the phase velocity describes how the wave's phase moves through space over time. Understanding this relationship clarifies the concept of phase velocity in wave mechanics.
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why is phase velocity v=w/k ?
 
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Let us look at a typical harmonic wave, f(x,t)=a\sin(kx-\omega{t})
Here, a,k,\omega are constants, where a is the amplitude, k the wave number and \omega the frequency.

Rewrite this in the following form:
f(x,t)=a\sin(k(x-\frac{\omega}{k}t))
Do you see that if x-\frac{\omega}{k}t=s where s is a CONSTANT, makes the value of f constant as well (equal to a\sin(ks))?
But that means, that the signal value a\sin(ks) can be regarded as MOVING ALONG THE POSITIVE X-DIRECTION WITH VELOCITY \frac{\omega}{k}!
For, (remembering that s is constant) we have the trajectory for our signal:
x=s+\frac{\omega}{k}t
and this simply shows what the propagation velocity of our signal is..
 
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"But that means, that the signal value can be regarded as MOVING ALONG THE POSITIVE X-DIRECTION WITH VELOCITYw/k !"
can you explain that a little clearer?
 
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