- #1

songoku

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- Homework Statement
- Find

$$\int \frac{x^3}{\sqrt{16x-x^8}}dx$$

- Relevant Equations
- u - substitution

trigonometry substitution

I tried using substitution ##u=\sqrt{16x-x^8}##, didn't work

Tried factorize ##x## from the denominator and then used ##u=\sqrt{16-x^7}##, didn't work

Tried using ##u=x^4## also didn't work

How to approach this question? Thanks

Tried factorize ##x## from the denominator and then used ##u=\sqrt{16-x^7}##, didn't work

Tried using ##u=x^4## also didn't work

How to approach this question? Thanks