Why is the Buzzer Always On in this Circuit?

AI Thread Summary
The circuit in question activates a buzzer when moisture is detected, utilizing both PNP and NPN transistors for amplification. The PNP transistor biases the NPN when moisture creates a conductive path between probes, allowing current to flow and sound the buzzer. If the probes are dry, both transistors remain off, preventing the buzzer from sounding. The circuit's effectiveness relies on the conductivity of rainwater, which is influenced by impurities. Proper labeling of components is suggested for clarity in discussions about the circuit.
dpeagler
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I have this circuit that I found on the internet and I see for the most part how it works. But for some reason I am misunderstanding something about it because it seems to me that the buzzer would always be on. Perhaps I am confused due to the use of both a pnp and an npn transistor (I only have experience with npn not pnp).

Also, if anyone sees any problems in the circuit please alert me as I have yet to test this circuit.

If anyone could help me in this endeavor it would be greatly appreciated.
 
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dpeagler said:
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... But for some reason I am misunderstanding something about it because it seems to me that the buzzer would always be on. ...

You are correct. As long as there is moisture/rain on the detector, the PNP transistor base will be biased causing a collector current that will turn on (saturate) the NPN transistor. When the NPN is on, the beeper will sound. Problem is, the circuit detects rain but you'll need to dry it out to stop the noise.
 

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When the gap between the probes is dry there is a near infinite resistance from the collector (and therefore the negative supply) to base of the 2N4403 transistor.

This transistor is connected to its emitter by a 100K resistor, but no current can flow so there is no voltage drop across this resistor.
So both ends of this resistor are at the same voltage.
So the base of the 2N4403 is at the same voltage as its emitter.

So the 2N4403 is off.

By similar reasoning the 2N4401 is also off since there is very high resistance from its collector supply to its base.
So the 1K resistor to its emitter also passes no current etc.

When the gap between the probes is wetted this introduces a modest resistance between the probes allowing current to flow from the battery negative through the wet probe resistance, the 1K resistor and the 100K resistor.

This sets up voltages to bias the 2N4403 on, so that the more the water, the lower the probe resistance and the greater the part of the battery voltage that appears across the 100K resistor. ie the wetter the probe the harder the transistor turns on.

Similarly when the 2N4403 turns on it passes collector current through the 220 ohma and 1K resistors, thus biasing the 2N4401 on and sounding the buzzer.

Both transistors contribute to the amplification of the small current passed through the water by the battery.
This is much easier to achieve with alternate pnp/npn (or npn/pnp) stages.

Incidentally it is much easier for all concerned to talk about a circuit if you label the resistors R1, R2 etc and the Transistors TR1, TR2 and so on, as well as giving values.
 
Would a small LED work just as well? The voltage in that area of the circuit should be high enough to overcome the diode drop correct? I'm just wondering because I don't think the lab I am working in has a buzzer comparable to the one in the diagram.
 
Yes, but put about 150 ohms in series with the LED.

This circuit depends on there being impurities in the rainwater as rainwater is basically distilled water and a poor conductor of electricity.
However, the impurities (mainly Carbon Dioxide, but also industrial pollutants) give the water some conductivity.
 
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