Why Is the Electric Potential Higher at Point P Than at Point Q?

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The discussion centers on the electric potential difference between points P and Q, with the conclusion that point P has a higher electric potential than point Q. The right-hand rule is referenced to analyze current direction, indicating that current flows from Q to P. It is clarified that the positive terminal of a voltage source is always at a higher potential than the negative terminal, regardless of power flow. The conversation emphasizes that when a voltage source delivers power, current flows from the negative to the positive terminal inside the source. Understanding these principles is crucial for correctly interpreting electric potential in circuits.
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Homework Statement


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Homework Equations


potential = kq1q2 / r

The Attempt at a Solution


The answer is D. Which states "The electric potential in P is higher than Q" is correct. But my answer is B. By right hand rule, the current goes from Q to P. The formula of potential has a positive sign. So I think Q has a higher potential as work is needed to move the protons from P to Q. Why am I wrong?
 
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Your right hand rule analysis correct but P is at a higher potential than Q. The conductor in the magnetic field is acting as a source. You can replace it with a battery. What is the direction of current inside a voltage source when it is delivering power?
 
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cnh1995 said:
Your right hand rule analysis correct but P is at a higher potential than Q. The conductor in the magnetic field is acting as a source. You can replace it with a battery. What is the direction of current inside a voltage source when it is delivering power?

Do you mean placing a battery in QP, then I get P is the positive terminal and Q is the negative terminal, so P has a higher potential . Thanks for reminding me the source is in the magnetic field.
 
Clara Chung said:
Do you mean placing a battery in QP
Yes. When a voltage source is delivering power, current flows from -ve to +ve terminal inside the source.
 
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cnh1995 said:
Yes. When a voltage source is delivering power, current flows from -ve to +ve terminal inside the source.
is positive terminal always have a higher potential even when a voltage source is delivering power?
 
Clara Chung said:
is positive terminal always have a higher potential even when a voltage source is delivering power?
Conventionally, +ve terminal is always at a higher potential than the -ve terminal (of the same source), irrespective of the power flow. If the current is flowing from +ve terminal to -ve terminal inside the component, it is absorbing power and if the current is flowing from -ve to +ve terminal inside the component, the component is acting as a source of power. Note that the current here is the conventional current. So, for a power delivering voltage source, current flows from -ve to +ve terminal inside the source and for a power absorbing voltage source, current flows from +ve to -ve terminal inside the source.
 
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