Why is the ground state eigenfunction in a symmetric hamiltonian also symmetric?

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The discussion centers on the symmetry of ground state eigenfunctions in quantum mechanical systems. It clarifies that the ground state is symmetric under coordinate inversion only if the Hamiltonian of the system is also symmetric. In systems with a symmetric Hamiltonian, all eigenfunctions are classified as either even (symmetric) or odd (antisymmetric). Since antisymmetric wavefunctions have nodes and must pass through zero, they cannot represent the ground state. Consequently, the ground state eigenfunction must be symmetric.
njoshi3
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Hi,
Why is that, the ground state eigenfunction in ANY quantum mechanical system is symmetric under inversion of co-ordinates?
 
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Originally posted by njoshi3
Hi,
Why is that, the ground state eigenfunction in ANY quantum mechanical system is symmetric under inversion of co-ordinates?

well first of all, this isn t true. the groundstate is only symmetric if the hamiltonian is also symmetric.

so let s assume that you had asked this question about any quantum system with a symmetric hamiltonian.

when there is a symmetric hamiltonian, all eigenfuctions must be either even or odd. that is, they must be either symmetric or antisymmetric.

an antisymmetric wavefunction necessarily passes through zero. therefore it has a node, therefore it cannot be the ground state.

therefore the ground state must be symmetric.
 
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