Why is the standard form of a linear equation significant in graphing?

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The standard form of a linear equation, ax + by = c, is significant because it can represent all types of lines, including vertical lines, which cannot be expressed in slope-intercept form (y = mx + b). This form allows for easier identification of key characteristics such as degree, constants, and potential factors, especially as equations increase in complexity. It also maintains a consistent format that simplifies the presentation and manipulation of equations. The ability to express vertical lines in standard form highlights its versatility compared to other forms. Overall, the standard form serves as a foundational representation in graphing linear equations.
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Why is the standard form of a linear equation ax + by = c? What is the significance of this particular way of writing the equation that makes it "standard"? When we graph a line, we always transform the equation into something else, such as the point-slope form, y = mx + b.

In other words, what is the equation, without transformation, used for?
 
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Well I've always been told that it's for presentation purposes. But then again I view that equation as more of a diophantine equation anyways.
 
I'm guessing a sorted polynomial form makes it easier to read and factor the thing? It doesn't really matter for a linear equation, but once you get higher degrees it does make a difference.

A quick glance at the first factor tells you the degree, you can easily locate the constant, you can quickly see if it is a complete square. If it was written as a slope, some of those would take longer.

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One advantage of that form is that every line can be written in that form. A vertical line, say one in which x is always 3, has the form x= 3, of course, which is ax+ by= c with a= 1, b=0, c= 3. It cannot be written in the form y= mx+ b because solving ax+ by= c for y involves dividing by b which, here, is 0. Additionally, in y= mx+ b y is necessairily a function of x. If x= 3, that is not true.
 
I picked up this problem from the Schaum's series book titled "College Mathematics" by Ayres/Schmidt. It is a solved problem in the book. But what surprised me was that the solution to this problem was given in one line without any explanation. I could, therefore, not understand how the given one-line solution was reached. The one-line solution in the book says: The equation is ##x \cos{\omega} +y \sin{\omega} - 5 = 0##, ##\omega## being the parameter. From my side, the only thing I could...

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