Why is the trace of jacobian=the divergence?

In summary, the trace of the Jacobian is equal to the divergence of a vector field, which can also be seen as the volume flow rate divided by the original volume in the vector field. The mathematical background behind this equality is that the trace of the total derivative of a differentiable map in a standard basis is equal to the sum of its partial derivatives, and this can be applied to a vector field as well. The trace and determinant of the Jacobian are useful invariants as they are independent of the coordinate system and represent the function without interference from the coordinate system. This can be seen in the example of a derivative where a coordinate dependent condition must be considered.
  • #1
marellasunny
255
3
What is the theoretical connection intuitively justifying that the trace of the jacobian=the divergence of a vector field? I know that this also equals the volume flow rate/original volume in the vector field but leaving that aside, what is the mathematical background behind establishing this equality?
 
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  • #2
Are you asking for a proof? The proof is trivial (it follows immediately from the form of the jacobian). Let ##U\subseteq \mathbb{R}^{n}## be open and let ##F:U\rightarrow \mathbb{R}^{m}## be differentiable at ##a\in U##. Then the matrix representation of the total derivative of ##F## at ##a##, in the standard basis ##S##, is given by ##(DF(a))_{S} = (\frac{\partial F^j}{\partial x^i}(a))##. We call this matrix representation the jacobian of such a map. Hence ##Tr(DF(a))_{S} = \sum\frac{\partial F^{i}}{\partial x^{i}}(a)##. Thus if ##X:U\subseteq \mathbb{R}^{3}\rightarrow \mathbb{R}^{3}## is a vector field and ##a\in U##, ##Tr(DX)_{S}(a) = \frac{\partial X^{1}}{\partial x^1}(a) + \frac{\partial X^{2}}{\partial x^2}(a) + \frac{\partial X^{3}}{\partial x^3}(a) = (\nabla\cdot X)(a)##.
 
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  • #3
Well the Jacobian it the derivative of the function in the f:V->V senses. So any other derivative can be found from it, in particular we like invariants of the Jacobian including the trace and determinant as they are coordinate independent and as such represent the function without interference.
 
  • #4
lurflurf said:
in particular we like invariants of the Jacobian including the trace and determinant as they are coordinate independent and as such represent the function without interference.

I think you meant "the trace and determinant are independent of the coordinate system".

Could you please explain the meaning of "represent the function without interference"?
 
  • #5
coordinate independent and independent of the coordinate system mean the same thing, but coordinate independent is shorter and sounds better. By "represent the function without interference" I mean that sometimes one uses coordinate dependent, but when one does she must always consider what is caused by the function and what is caused by the coordinate system. A condition must be considered in terms of the coordinates. A simple example if we define a derivative (x^2f)' the condition f'=0 becomes ((x^2f)'-2xf)/x^2=0 when might cause confusion.
 

1. Why is the trace of Jacobian equal to the divergence?

The trace of Jacobian is equal to the divergence because it is a mathematical property of a vector field that measures the rate at which the field spreads or converges at a point. The Jacobian matrix, which represents the derivative of a vector field, contains the partial derivatives of the vector field with respect to each coordinate direction. The trace of this matrix is equal to the sum of these partial derivatives, which is equivalent to the divergence of the vector field.

2. What is the physical significance of the trace of Jacobian being equal to the divergence?

The physical significance of the trace of Jacobian being equal to the divergence is that it provides information about the behavior of a vector field at a specific point. A positive divergence indicates that the field is spreading outwards, while a negative divergence indicates that it is converging inwards. The magnitude of the divergence represents the strength of this behavior. This information is crucial in many scientific fields, such as fluid dynamics, where vector fields are used to model the flow of fluids.

3. Can the trace of Jacobian be negative?

Yes, the trace of Jacobian can be negative. This occurs when the vector field is converging inwards at a point, meaning that the partial derivatives of the field in each coordinate direction are negative. In this case, the divergence will also be negative, indicating the strength of the convergence.

4. How is the trace of Jacobian related to the Laplacian operator?

The Laplacian operator is a differential operator that is defined as the divergence of the gradient of a scalar field. This means that the Laplacian operator is equal to the trace of the Hessian matrix, which is the second derivative of the scalar field. Therefore, the Laplacian operator is indirectly related to the trace of Jacobian, as it involves the divergence of a vector field.

5. Why is the trace of Jacobian important in vector calculus?

The trace of Jacobian is important in vector calculus because it provides a way to measure the behavior of a vector field at a specific point. This information is crucial in many mathematical applications, such as optimization problems, as well as in various scientific fields, such as fluid dynamics and electromagnetism. Additionally, the trace of Jacobian is related to other important concepts in vector calculus, such as the Laplacian operator and the Hessian matrix.

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