Why is there a differential in an indefinite integral?

Click For Summary
SUMMARY

The discussion centers on the necessity of the differential notation "dx" in the context of indefinite integrals, specifically antiderivatives. Participants clarify that the differential indicates the variable of integration, similar to how "d/dx" specifies the derivative's variable. The Fundamental Theorem of Calculus is highlighted as the connection between integrals and antiderivatives. Additionally, there is criticism of the terminology used in textbooks, which may confuse students regarding the relationship between integration and antiderivatives.

PREREQUISITES
  • Understanding of basic calculus concepts, including integrals and derivatives.
  • Familiarity with the Fundamental Theorem of Calculus.
  • Knowledge of differential notation in calculus.
  • Experience with substitution techniques in integration.
NEXT STEPS
  • Study the Fundamental Theorem of Calculus in detail.
  • Explore the role of differentials in integration techniques.
  • Research various notations for antiderivatives and their implications.
  • Practice integration techniques, including u-substitution and integration by parts.
USEFUL FOR

Students of calculus, mathematics educators, and anyone seeking to deepen their understanding of the relationship between integrals and antiderivatives.

Jow
Messages
69
Reaction score
0
I understand why a definite integral of the form ^{b}_{a}∫ƒ(x)dx has the differential dx in it. What I don't understand, and what my teacher hasn't explained is why an indefinite integral (i.e. an antiderivative) requires the differential. Why does ∫ƒ(x)dx require that dx to mean "anti-differentiate"? To put it another way, why is the notation for the antiderivative an integral? It's obviously more than a question of notation, however, as without the differential techniques like u-substitution don't work. I hope this question makes sense, but this is something that has been bothering me for a while now. I figured my teacher would get to it eventually, but he hasn't yet.
 
Physics news on Phys.org
Short answer. It tells you what is the variable for integration. Analog is d/dx to tell you the derivative is with respect to x.
 
Why would techniques like substitution not work, or be dependent on notation? You could replace dx by "Ix" if you wanted and substitution would still work!

\int f(u(x))u'(x) Ix = \int f(u) Iu
 
Jow said:
To put it another way, why is the notation for the antiderivative an integral?

It's actually the other way around; we use the notation for integrals to talk about antiderivatives. The Fundamental Theorem of Calculus provides a link between the two concepts.

I am not aware of any notation specifically used to talk about antiderivatives, though I propose we begin using ##\frac{d^{-1}}{dx}f## to denote the family of functions whose derivatives are ##f## (which I'm certain will never happen). Most modern textbooks that I'm familiar with either don't have a notation until integration is introduced or they "cheat" and use the usual notation, ##\int f\ dx##, before students learn about integration with little to no explanation for why that is the chosen notation.

In my opinion, referring to antiderivatives as "indefinite integrals" and denoting them by ##\int f\ dx## is an unnecessary abuse of terminology and notation that serves more to confuse students (and some calculus teachers, I'm sure) than it helps them communicate mathematical ideas.
 

Similar threads

  • · Replies 11 ·
Replies
11
Views
2K
  • · Replies 4 ·
Replies
4
Views
3K
  • · Replies 6 ·
Replies
6
Views
3K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 11 ·
Replies
11
Views
35K
  • · Replies 2 ·
Replies
2
Views
1K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 9 ·
Replies
9
Views
3K
  • · Replies 10 ·
Replies
10
Views
2K