Why is there a moment generated by the 0.8NB force at Point A?

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The discussion focuses on the moment generated by a 0.8NB force at Point A, questioning its relevance in calculations. It clarifies that the moment should consider the perpendicular distance from the line of action of the force to Point A, which is critical for accurate torque calculations. The distinction between a frame and a truss is emphasized, noting that trusses only handle tensile and compressive forces without bending moments. The participants agree that the perpendicular distance for the horizontal component of the force must be measured correctly to determine its contribution to the moment about Point A. Ultimately, understanding the line of action and its distance from the point is essential for accurate moment calculations.
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Homework Statement


for the moment about A , why there 's moment generated by the forces of 0.8NB (circled part) ?

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The Attempt at a Solution


I think it's not necessary to include the moment 0.8NB(4) because the d = 0.4m is not measured directly from point A ...it's measured from the red circled part ...
 

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1. It's not 0.4 m but 4 feet and it's the vertical distance between B and A
and that is multiplied with the horizontal component of NB
2. the 10 feet is the horizontal distance etc.
 
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btw, this is not a truss, but a frame. Trusses are designed only under tensile and compression forces, no bending moments
 
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sakonpure6 said:
btw, this is not a truss, but a frame. Trusses are designed only under tensile and compression forces, no bending moments
In the diagram attached below , we can see that the d (prepedicular distance) for NBy is measured directly from A , but for the NBx ( blue part) , it's measured directly from a point which is 10 m from A . So , for the moment 4NBx , it's not moment about A , am i right ? Why the author consider it in the calculation ?
 

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fonseh said:
So , for the moment 4NBx , it's not moment about A , am i right
No. The line of action of NBxis at a perpendicular distance of 4 feet from A
 
BvU said:
No. The line of action of NBxis at a perpendicular distance of 4 feet from A
why ?
 
upload_2017-1-12_11-19-59.png


A force acts along a line of action. You can always move it along that line without changing anything.
Only when you move a force perpendicular to its line of action you have to add a torque.

To reassure yourself: calculate the perpendicular distance of the line of action of NB itself to the point A and compare with the total torque from x and y components.
 
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