Why Is Weight Expressed in Scientific Notation in Physics Problems?

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Weight is expressed in scientific notation in physics to simplify the representation of large numbers, making calculations easier and clearer. In the example provided, the weight of a 65kg student is calculated as 637N, which is then rounded and expressed as 6.4 x 10^2N to reflect significant figures accurately. This notation is particularly useful for larger values, allowing for concise communication of results. The rounding to two significant figures aligns with the precision of the given mass. Understanding scientific notation and significant figures is essential for accurately interpreting and presenting physics problems.
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Hey,
I'm taking physics as a learn-at-home kinda course to get into school for electrical. I had a question about some of the logic and reason behind what the book is showing me as it doesn't explain much. The example question they gave is as follows:

Determine the weight of a 65kg student on earth( g= 9.8m/s2 [down]).

Given - g= 9.8m/s2 [down]
m = 65kg

Required - Fg=?

Equation - Fg = mg

Solution - Fg = (65kg)(9.8ms2)
Fg = 637N
Fg = 6.4 x 102N

More or less I wanted to know why the 637N was broken up to 6.4 x 102 and how I would go about extrapolating this from every question I come across from now on.

Any info is appreciated, I am new to physics and suck at math in general...

p.s. the g's in the equation should have an arrow pointing to the right over them but I have no clue how to write that on this thing...

Thanks!
 
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Its just a convention man..more applicable for bigger numbers...like you can write 10000000 or 10^7 they would mean the same thing...its just for the ease of writing
 
YayPhysics said:
More or less I wanted to know why the 637N was broken up to 6.4 x 102 and how I would go about extrapolating this from every question I come across from now on.
They are just expressing the weight using scientific or exponential notation. (See: http://en.wikipedia.org/wiki/Scientific_notation" ) Note that they rounded off the answer to 2 significant figures instead of 3, which is more realistic since you only have the mass to 2 significant figures.


p.s. the g's in the equation should have an arrow pointing to the right over them but I have no clue how to write that on this thing...
While the acceleration is a vector, which you could express using that arrow notation, g itself is just the quantity 9.8 m/s^2.
 
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