I Why the GUT epoch ended at ~10^-36 s ?

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I read that the GUT epoch is estimated to have ended at around 10-36 s, but I can't find any proof or derivation for this. Anyone knows ?
 
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DoobleD said:
I read

Where? Please give a specific reference.
 
PeterDonis said:
Where? Please give a specific reference.

Sure :
The list goes on, but I didn't find a source with a proof or at least some qualitative justification for this.

<Moderator's note: Link changed due to possible copyright violation>
 
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DoobleD said:
I read that the GUT epoch is estimated to have ended at around 10-36 s, but I can't find any proof or derivation for this. Anyone knows ?

Try using (3.2.68) of Daniel Baumann's (Cambridge) excellent cosmology lecture notes
http://www.damtp.cam.ac.uk/user/db275/Cosmology/Lectures.pdf
to find ##t_\rm{GUT}## for ##T_\rm{GUT} \approx 10^{15} ~\rm{GeV}## and ##g_* \approx 10##.

PeterDonis said:
Where? Please give a specific reference.

Within one or two orders of magnitude, it is ubiquitous in the literature, e.g., on page 190 of the second edition of the often-used text "Introduction to Cosmology" by Barbara Ryden.
 
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George Jones said:
Try using (3.2.68) of Daniel Baumann's (Cambridge) excellent cosmology lecture notes
http://www.damtp.cam.ac.uk/user/db275/Cosmology/Lectures.pdf
to find tGUTtGUTt_\rm{GUT} for TGUT≈1015 GeVTGUT≈1015 GeVT_\rm{GUT} \approx 10^{15} ~\rm{GeV} and g∗≈10g∗≈10g_* \approx 10.

Seems to be it, thank you ! I get, using ##T_\rm{GUT} \approx 10^{15} ~\rm{GeV} = 10^{18} MeV## :

##t \approx \frac{9}{4\sqrt{10}T^2} \approx 7 \times 10^{-37} s##, which is close enough.

One thing I'm not sure about though is why the choice of ##g_* \approx 10## degrees of freedom ?
 
DoobleD said:
Seems to be it, thank you ! I get, using ##T_\rm{GUT} \approx 10^{15} ~\rm{GeV} = 10^{18} MeV## :

##t \approx \frac{9}{4\sqrt{10}T^2} \approx 7 \times 10^{-37} s##, which is close enough.

I have a few books that give expressions equivalent to Baumann's (3.2.68), but, as far as I can see, I have only one book that explicitly uses this expression to estimate ##t_\rm{GUT}##, "Introduction to General Relativity" by Lewis Ryder.

DoobleD said:
One thing I'm not sure about though is why the choice of ##g_* \approx 10## degrees of freedom ?

We are only looking at order of magnitude stuff. Even so, this is probably too small by an order of magnitude or so, since ##T_\rm{GUT} \approx 10^{15} ~\rm{GeV} ## or ##T_\rm{GUT} \approx 10^{16} ~\rm{GeV}## for the Minimal Supersymmetric Standard Model (MSSM), which has loads of particle species.
 
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George Jones said:
We are only looking at order of magnitude stuff. Even so, this is probably too small by an order of magnitude or so, since TGUT≈1015 GeVTGUT≈1015 GeVT_\rm{GUT} \approx 10^{15} ~\rm{GeV} or TGUT≈1016 GeVTGUT≈1016 GeVT_\rm{GUT} \approx 10^{16} ~\rm{GeV} for the Minimal Supersymmetric Standard Model (MSSM), which has loads of particle species.

Right, ##g_*## doesn't change much the estimation anyway. I was just curious of what those degrees mean, but doesn't really matter.

George Jones said:
I have a few books that give expressions equivalent to Baumann's (3.2.68), but, as far as I can see, I have only one book that explicitly uses this expression to estimate tGUTtGUTt_\rm{GUT}, "Introduction to General Relativity" by Lewis Ryder.

Thanks, I got the book and found it indeed, on page 384. I'll keep those two references.
 
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