Will an infinite plane of charge flux generate flux through itself?

AI Thread Summary
An infinite plane of charge does not generate electric flux through a hole cut into it, as the electric field within the hole is zero due to symmetry. When considering flux, it is typically associated with closed surfaces, making the scenario of an infinite plate somewhat counterintuitive. As the area of the hole decreases, the net electric field remains zero, confirming no flux enters or exits. If the infinite plate were part of a closed conducting surface, the electric field in the hole would be half of the external field. The discussion highlights the complexities and nuances of electric fields in theoretical physics.
ozone
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I just have a quick question, and I'm guessing the answer is no but I wanted to make sure that this was sensible. In general whenever we consider flux we think of some kind of closed surface or a scenario where charge closes back on itself.

If I were to cut a hole in an infinite plate of charge, would there be any flux through that hole from the plate of charge? My guess is that we can take the limiting case as a pillbox on the hole shrinks, and we will see that no flux is entering or exiting (I think the net E-field ought to be 0 in the hole). However it doesn't make sense to me why anyone would ask this question then.
 
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The electric field in the hole must be zero, yes. You can see that by symmetry arguments alone. Why would anybody ask that question? Because they want to know the answer, and so did you...
 
If the plate is part of a closed conducting surface, the E field in the hole will be E_0/2.
 
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