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## Homework Statement

- A ball is thrown at 22 m/s at 45 degrees to the horizontal. A 5 foot tall fence is located 100 meters away. Does the ball make it over the fence?

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- Thread starter keithcuda
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- A ball is thrown at 22 m/s at 45 degrees to the horizontal. A 5 foot tall fence is located 100 meters away. Does the ball make it over the fence?

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SteamKing

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What's the deal with v

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Quantum Defect

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## Homework Statement

- A ball is thrown at 22 m/s at 45 degrees to the horizontal. A 5 foot tall fence is located 100 meters away. Does the ball make it over the fence?

## Homework Equations

View attachment 77761

## The Attempt at a Solution

The first three equations are correct. You found the initial velocities in the x and y directions.

The motions in the x and y directions are independent. You can write a very simple equation for the motion in the x direction: x = x_0 + v_x * t (constant velocity, no acceleration). You can write a second equation for the motion in the y-direction. For this one, there is acceleration. [Be careful with the signs on the initial velocity and acceleration, here].

See: https://www.physicsforums.com/showpost.php?p=905663&postcount=2 for the equations for motion in one-dimension.

For the condition: "Ball over the fence", how would you define this with particular values for x and y?

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CWatters

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What's the deal with v_{f}- v_{i}= -31.12? [You need to show units in your calculations always.] What does this even mean, in terms of the travel of the ball?

Here is my image and drawing with all of the units shown.. Sorry for not including them earlier.

View attachment 77770

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Bystander

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Who's throwing? Randy Johnson? Or Warwick Davis?

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Roy Hobbs ;)Who's throwing? Randy Johnson? Or Warwick Davis?

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SteamKing

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Your attachment can't be opened.Here is my image and drawing with all of the units shown.. Sorry for not including them earlier.

View attachment 77770

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Your attachment can't be opened.

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Quantum Defect

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Here is my image and drawing with all of the units shown.. Sorry for not including them earlier.

View attachment 77770View attachment 77771

Ok, I understand what you are doing now.

On the line with Delta v, you are stating that at the point that the ball impacts the ground, the downward velocity is the same magnitude as the upward velocity at the launch, but with opposite direction. You use the calculated Delta v and g to calculate the time aloft, and you use the horizontal component of the velocity times the time aloft to calculate the distance traveled. You note that since the distance traveled (49 m) < 100 m, the ball hits the dirt in front of the wall.

This looks good to me.

I would suggest adding some words to describe the equations -- to show that you know what you are doing. If you screw up the calculation (arithmetic error) but have the correct physics, your professor might give you some partial credit...

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Ok, I understand what you are doing now.

On the line with Delta v, you are stating that at the point that the ball impacts the ground, the downward velocity is the same magnitude as the upward velocity at the launch, but with opposite direction. You use the calculated Delta v and g to calculate the time aloft, and you use the horizontal component of the velocity times the time aloft to calculate the distance traveled. You note that since the distance traveled (49 m) < 100 m, the ball hits the dirt in front of the wall.

This looks good to me.

I would suggest adding some words to describe the equations -- to show that you know what you are doing. If you screw up the calculation (arithmetic error) but have the correct physics, your professor might give you some partial credit...

Sorry I wasn't as clear earlier. It is hard for me to figure out what exactly I need to find and when. I found an example to my problem on Khanacademy.org and just watched it a few times and then used what i gained from the video to solve my problem. I was wanting to double check my approach and see if there was a different way to solve this or if the way i went about it is how it would be normally solved.

Cheers

Keith

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TSny

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How high can that ball bounce?

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OH boy! Ummm...How high can that ball bounce?

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CWatters

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Sorry it took me a little while to get back, been working. I don't get weekends off very much

The ball was thrown at a 45 degree angle. So it would also fall at a 45 degree angle.

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