Will this stick spin if it has no pivot?

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SUMMARY

A long, one-dimensional rod of mass M and length L, when struck at its end in the +X direction, will indeed spin despite having no pivot or external forces acting on it. The application of force at a non-zero distance from the center of mass generates a torque, leading to rotational motion. The analysis confirms that the impulse experienced by the atoms at the end of the rod results in a clockwise torque due to the restoring forces from neighboring atoms, thus causing the rod to spin as it translates.

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  • Basic knowledge of impulse and momentum transfer
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Albertgauss
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Hi all,

Here is what I am trying to understand qualitatively. It is NOT a homework problem:

A long, one-dimensional rod of mass M and length L is in free space. There is no gravity, no forces, and no pivot. Its just a rod sitting there, floating, with nothing else around. Let's say its L=0 end is at the origin (y=0), and its L=L end at a positive y=L. Suppose I strike the y=L end of the stick in the +X direction. By Newton's Inertial Law, the stick should move translationally as I transferred momentum to it. But will it spin? I can't figure that out.

I thought perhaps that it might. I tried to think of the stick as comprised of many atoms attached to each other by springs. I made some simplifying assumptions. The atoms at the y=L of the stick that receive the WHACK will experience a force via an impulse in the pure positive X direction as long as I am in contact (however brief) with the y=L end. The atoms at the y=L end will also experience a restoring force due to their neighboring atoms trying to pull them back. That restoring force would point towards the third quadrant. The restoring force and my impulse force would produce a net force pointing towards the fourth quadrant, and hence I would have a clockwise torque. Thus, I would conclude the rod will indeed spin as it moves off.

How am I doing?
 
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It will spin.

The force applied is at a non-zero distance from the centre of mass.
 

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