Which Will Undergo Faster Williamson Ether Synthesis?

AI Thread Summary
The discussion centers on determining which compound, 3-Chlorobutan-1-ene or 1-Bromobutane, undergoes faster Williamson ether synthesis. The consensus is that the reaction typically follows an SN2 mechanism, favoring 1-Bromobutane due to the weaker C-Br bond compared to the C-Cl bond in 3-Chlorobutan-1-ene. The presence of a stable carbocation is less relevant in this context, as SN1 reactions are less favorable for ether synthesis due to potential competition from elimination products. Key factors influencing the reaction include the strength of the leaving group and steric hindrance. Ultimately, 1-Bromobutane is identified as the better choice for faster ether synthesis.
Suraj M
Gold Member
Messages
596
Reaction score
39

Homework Statement


Which will undergo faster Williamson ether syntehsis
It was either faster or better, I'm not sure

A)3-Chlorobutan-1-ene
B)1-Bromobutane

Homework Equations

The Attempt at a Solution


I thought option A because of its alylic position it will form a stable carbocation (and through SN1)
Is it correct? Or is it B because bromine is more weakly bound to the primary carbon

Thank you :-)
 
Physics news on Phys.org
What mechanism is involved in Williamson ether synthesis, SN1 or SN2? What factors are most important for reactions of that type?
 
  • Like
Likes Greg Bernhardt
The mechanism depends on the reactants right?
What factors? I'd say driving force of the stabilized carbocation if it's SN1 else steric factor and strength of the CX bond for SN2?
Is that right?
 
Suraj M said:
The mechanism depends on the reactants right?
You should double check what your text says about the mechanism of Williamson ether synthesis.
 
Last edited:
Oh always SN2?
Then in that case it's option B right?
 
Yes. If you were to try to form an ether via an SN1 reaction, you would probably have too much competition from the E1 product.
 
Ah okay
Thanks Ygggrasil ! :-)
 
Back
Top