Wires and potential difference

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SUMMARY

In electrostatics, equipotential surfaces are defined as conductors in electrostatic equilibrium, where no charges are in motion. A wire carrying current is not an equipotential surface due to the presence of a potential difference between its ends, which is necessary for current flow. While it is accurate to state that a wire without an imposed potential difference is equipotential and has no current, in practical circuit analysis, it is often approximated that the ends of a wire are equipotential to simplify calculations, despite minor voltage differences.

PREREQUISITES
  • Understanding of electrostatics and equipotential surfaces
  • Knowledge of electric current and potential difference
  • Familiarity with basic circuit theory
  • Concept of electrostatic equilibrium
NEXT STEPS
  • Study the concept of equipotential surfaces in detail
  • Learn about electric current and its relationship with potential difference
  • Explore circuit analysis techniques, focusing on approximations in wire behavior
  • Investigate electrostatic equilibrium and its implications in various physical scenarios
USEFUL FOR

Students in physics, electrical engineering majors, and anyone interested in understanding the principles of electrostatics and circuit theory.

maccha
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Recently in physics I've learned that equipotential surfaces are always conductors in electrostatic equilibrium.. so no moving charges. I'm a little confused, then, of how a wire carrying current is considered an equipotential? If charges are moving how can the potential be constant?
 
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I don't understand your question because a wire with current moving through it is NOT an equipotential surface- for one thing, in order to have current there must be a potential difference between the two ends. Of course, in order to have a current in it, differing potential must be applied to both ends of the wire. A wire without an imposed potential difference is an "equipotential"- and has no current in it.

(Since this is a question and NOT "learning material" I am moving it to "general physics".)
 
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HallsofIvy is correct, however if you are in a circuits class then you will often make the useful approximation that the ends of a wire are equipotential because it is simply too tedious to keep track of a couple of nanovolts here and there.
 

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