Wood block sliding on 25 degree angle

AI Thread Summary
To determine the coefficient of kinetic friction for a wooden block sliding down a 25-degree inclined plane at a constant velocity of 6 m/s, it's essential to draw a Free Body Force diagram and establish a coordinate system aligned with the incline. The forces acting on the block include gravitational force, normal force, and friction. Since the block moves at a constant velocity, the net force along the incline is zero, indicating that the force of friction equals the component of gravitational force acting down the slope. By calculating these forces, one can derive the coefficient of kinetic friction. This approach effectively simplifies the problem and leads to the solution.
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A wooden block slides directly down an inclined plane, at a constant velocity of 6 m/s. How large is the coefficient of kinetic friction, if the plane makes an angle of 25 degrees with the horizontal?
 
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What have you done? show some work.
 
f=UN = 6(0.4) not sure how to begin with this problem and how to find the coefficient
 
First of all, what you should do in every problem of this type, is to choose an appropriate set of axis and draw the Free Body Force diagram.
In the inclined plane questions, it is easier to solve a problem if you choose the co-ordinate axis (ie, x&y axis) as along the plane and perpendicular to the plane.
Next, identify all the forces acting on the block and find the components of each force along the axis.
Since the body is not accelerating, what is the sum of the forces acting along the plane? Can you find the value of friction from this?
 
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