Work and Energy: Find the Angle of Force - 65 Characters

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Homework Help Overview

The discussion revolves around a physics problem related to work and energy, specifically determining the angle of force acting on a body moving a certain distance under a given force. The context involves calculating work done using the formula involving force, distance, and the cosine of the angle between them.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the application of the work formula and the relationship between work, force, distance, and angle. There are inquiries about how to visualize the problem and the correct use of trigonometric functions to find the angle.

Discussion Status

Several participants have provided insights into the calculations and the use of inverse cosine to determine the angle. There is an ongoing exploration of the implications of the cosine value obtained and its relation to the angle, with some participants expressing confusion about the calculations and the concept of inverse functions.

Contextual Notes

Participants note the importance of understanding basic trigonometric values and their memorization for solving similar problems in the future. There is also mention of the need for clarity on the definitions and assumptions related to the problem setup.

alijan kk
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Homework Statement


A body moves a distance of 10 meter along a straight line under the action of a force of 5 Newtons. If work done is 25 joules, the angle which the force takes with the direction of motion of the body is:
a: 0 degree
b: 30 degree
c: 60 degree
d: 90 degree

Homework Equations


work=fdcostheta

The Attempt at a Solution


what formula should we use to get the degree or how to figure out it by making a picture?
 
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Based on the work's definition, to be honest, the more precise version of what you wrote in the Relevant equations, you have to find ##F\cdot d,## since the force is a constant vector here. Hence by what you had, you can get ##W=F\cdot d=|F||d|\cos\theta,## which can lead you to what you want.
 
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tommyxu3 said:
Based on the work's definition, to be honest, the more precise version of what you wrote in the Relevant equations, you have to find ##F\cdot d,## since the force is a constant vector here. Hence by what you had, you can get ##W=F\cdot d=|F||d|\cos\theta,## which can lead you to what you want.

work = FDcos
25=5*10*cose
25=50*cos
cos=25/50
cos=0.5

but what now? 1/2 or 0.5 is equalt to what?? help
 
work = FDcos
25=5*10*cose
25=50*cos
cos=25/50
cos=0.5

but what now? 1/2 or 0.5 is equalt to what?? help
 
The value ##0.5## you get is the cosine of the angle ##\theta,## which the the angle of the force and the displacement. Do you realize these?
 
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Inverse cos (0.5)=60
 
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tommyxu3 said:
The value ##0.5## you get is the cosine of the angle ##\theta,## which the the angle of the force and the displacement. Do you realize these?

yes but on calculator the value of cosetheta is 0.99?
can you get the answer of the given options above?
 
Now the question is given ##\cos\theta=0.5## and you have to find the ##\theta## between ##0## to ##180## degrees. Right?
 
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Parsifal1 said:
Inverse cos (0.5)=60[/QUOTEo
OH! yes the inverse of 0.5 is 60 !
but why we are using inverse cosine?
 
  • #10
tommyxu3 said:
Now the question is given ##\cos\theta=0.5## and you have to find the ##\theta## between ##0## to ##180## degrees. Right?
yes it is 60 by using inverse cosine theta !
 
  • #11
That's how you find x in cos(x)
 
  • #12
You don't have to apply the idea of inverse function, though the same, but just have to know what you want, with some basic knowledge of trigonometry, like ##\cos 60^{\circ}=\frac{1}{2}.##
 
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  • #13
25=(5*10)cos(x)
25/(5*10)=cos(x)=0.5
cos^-1 (0.5)=60
 
  • #14
Parsifal1 said:
That's how you find x in cos(x)
oh! thank you for your quick help. appreciat
 
  • #15
tommyxu3 said:
You don't have to apply the idea of inverse function, though the same, but just have to know what you want, with some basic knowledge of trigonometry, like ##\cos 60^{\circ}=\frac{1}{2}.##
yes you are right if have this value memorized i would have done thi question in seconds thankyou i will memorize cos30 cos60 and cos90 values right?
 
  • #16
Parsifal1 said:
25=(5*10)cos(x)
25/(5*10)=cos(x)=0.5
cos^-1 (0.5)=60
thanks
 
  • #17
If you keep learning other physics knowledge, then you'll keep being with these basic concepts, and finally you will memorize, or say acquire, them naturally.
 
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  • #18
alijan kk said:

Homework Statement


A body moves a distance of 10 meter along a straight line under the action of a force of 5 Newtons. If work done is 25 joules, the angle which the force takes with the direction of motion of the body is:
a: 0 degree
b: 30 degree
c: 60 degree
d: 90 degree

Homework Equations


work=fdcostheta

The Attempt at a Solution


what formula should we use to get the degree or how to figure out it by making a picture?
60°
 
  • #19
A@bhishek said:
60°
yes you are right , this question is solved
 

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