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A freight company uses a compressed spring to shoot 1.80 kg packages up a 1.0-m-high frictionless ramp into a truck, as the figure shows. The spring constant is 337 N/m and the spring is compressed 34.0 cm.

A) What is the speed of the package when it reaches the truck?

B) A careless worker spills his soda on the ramp. This creates a 50-cm-long sticky spot with a coefficient of kinetic friction 0.30. Will the next package make it into the truck? Yes or No?

Okay....For Part A this is what I did but it was wrong

First I said F_s=-k x= 337(.34) = 114.38

with this I said that 114.38=1/2mv^2 v=11.28

The F_w=1/2mv^2=ma=1.8*-9.8=-17.64

W=F_w*D=F_w=17.64

W= the change in KE

KE_f=W+KE_i

KE_f=96.74

1/2mv^2=96.74

so v=10.36

That is wrong and I don't know how to get the right answer could someone help?

Part B will probably make more sense after I solve the first part but could someone help me with the setup?

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# WORK by Constant Force Argh help

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