Work done by a person climbing stairs

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To calculate the work done by a 52.98 kg person climbing stairs, the force acting against gravity must be determined using the equation w=F•d, where F is the gravitational force (mass times acceleration due to gravity). The height of the stairs is 0.20 m, and the time taken to climb them is 2.96 seconds. It is clarified that if the person climbs at a constant speed, the net force is zero, meaning the applied force equals the gravitational force. The power required can then be calculated in watts, which is joules per second. Understanding these concepts is essential for solving the problem accurately.
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Homework Statement


Calculate the work done by a 52.98 kg person, who climbs a set of 0.20 m tall stairs (starting from rest) in 2.96s.
Calculate the power required to achieve this.


Homework Equations


w=F•d

The Attempt at a Solution


My issue with this question has been identifying the force which is acting in the situation. I know that Fg applies (mass • 9.81 m/s) and that there must be an applied force of some sort because the person is moving (working against gravity, I suppose?), but I am not sure which information I should use to calculate the "F" variable in the w=F•d equation. I think they want the power in watts (Joules per second).
 
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Hi Sen.Lemonsnout! Welcome to PF! :smile:

Assume that he climbs at a constant speed …

then the net force is zero, so the force he uses is … ? :wink:​
 
Thanks- I was definitely overthinking things!
 
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