Work done by external force in a gravitational field.

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SUMMARY

The discussion focuses on calculating the work done by an external agent to move a 212 g sphere (m3) between two fixed spheres of masses 2.53 kg (m1) and 7.16 kg (m2) located 1.56 m apart. The correct formula for the work done is Wext = Gm3m2(1/0.42 - 1/1.14) + Gm3m1(1/1.14 - 1/0.42), which accounts for the gravitational forces acting on m3 as it is moved. The positive sign in the second term indicates work done against gravitational attraction, confirming that the total work is the sum of the work done moving away from one mass and towards another.

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moatasim23
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Homework Statement



Spheres of masses m1 2.53kg and m27.16kg are fixed at a distance 1.56m apart centre to centre.A m3 212 g sphere is positioned 42cm from the 7.16 kg fromcentre of 7.16 kg sphere along the line of centres.How much work must be done by ext agent to move thesphere of 212 g sphere along the line of centres and place it 42 cm from the centre of sphere of mass 2.53 kg sphere?Assume the 212 g sphere to be moved bw the two spheres.

Homework Equations



Wext(External)=-Wg(gravitational)

The Attempt at a Solution


Wext=Gm3m2(1/.42-1/1.14)-Gm3m1(1/1.14-1/.42)
Which is not giving the desired result of 98.5pJ.
But if I take
Wext=Gm3m2(1/.42-1/1.14)+Gm3m1(1/1.14-1/.42) the answer gets right.But why should it be a positive sign?
 
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hi moatasim23! :smile:

(try using the X2 button just above the Reply box :wink:)
moatasim23 said:
Spheres of masses m1 2.53kg and m27.16kg are fixed at a distance 1.56m apart centre to centre.A m3 212 g sphere is positioned 42cm from the 7.16 kg fromcentre of 7.16 kg sphere along the line of centres.How much work must be done by ext agent to move thesphere of 212 g sphere along the line of centres and place it 42 cm from the centre of sphere of mass 2.53 kg sphere?Assume the 212 g sphere to be moved bw the two spheres.

so m3 starts 0.42 from one sphere and 1.14 from the other sphere, and finishes the other way round
… Wext=Gm3m2(1/.42-1/1.14)+Gm3m1(1/1.14-1/.42) the answer gets right.But why should it be a positive sign?

why not?

one is the work done moving it away from one sphere, the other is the work done moving it towards the other sphere, so the work done should have opposite signs, so your formula should have a + :confused:
 
tiny-tim said:
hi moatasim23! :smile:

(try using the X2 button just above the Reply box :wink:)


so m3 starts 0.42 from one sphere and 1.14 from the other sphere, and finishes the other way round


why not?

one is the work done moving it away from one sphere, the other is the work done moving it towards the other sphere, so the work done should have opposite signs, so your formula should have a + :confused:

That is what I am saying work done should have opposite signs.Taking both works to be positive does this means they hv opposite signs?How?
 
(just got up :zzz:)

not following you :confused:

your first bracket is negative, and your second bracket is positive, so they have opposite signs, as expected (and so you add them)
 

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