# Work done by forces

1. Nov 26, 2006

### AznBoi

Okay I kind of get this problem but not completey. Please see if I'm going in the right direction and guide me through it. Thanks!!

Here is the Problem: A 5kg block is pushed 3m up a vertical wall with constant speed by a constant force of magnitude F applied at an angle of theta=30 degrees with the horizontal. If the coefficient of kinetic friction between block and wall is 0.30, determine the work done by a) F, b) the force of gravity, and c) the normal force between block and wall. d) By how much does the gravitational potential energy increase during this motion?

Here is my work:
First of all I solved for the F force and I got 208 N
So then do I have to plug the force into the equation: W=Fcos(theta)(displacement) ??

Then it would be: 208cos30(3m) right??

For b) you need to find the work force of gravity.
So, W=(9.8m/s^2)cos180(3m)??

for c) normal force between block and wall.
would it be zero?? because the block moves upward and the normal force would be perpendicular to the displacement.

for d) How do you find how much the gravitational potential energy increases by? Do you use Usubi+Ksubi=Usubf+Usuf

2. Nov 26, 2006

### OlderDan

You have a problem with the angle. Potential energy increase is the same as always. Your equation is fine.

3. Nov 26, 2006

### AznBoi

What do you mean I have a problem with the angle?? Are all of the problems that I attempted right?

4. Nov 26, 2006

### Dorothy Weglend

I think he is talking about the work done by the force. 30 degrees is not the angle you should use, if I am understanding this problem correctly.

It is only the component of the force in the direction of the motion that is doing any work.

Dorothy

5. Nov 26, 2006

### AznBoi

I think 30 degrees is the angle that you need to use for the Fore F because it is being applied diagonally 30 degrees from the horizontal upwards.

6. Nov 26, 2006

### Dorothy Weglend

Just a suggestion, but a closer look at the definition of the angle in that particular formula would be a good idea. Hint: It's the angle between two vectors.

Dorothy

7. Nov 26, 2006

### AznBoi

oh so if the angle is 30 degrees from the horizontal. and the displacement is 90 degrees. would it be 90-30=60 degrees?

8. Nov 26, 2006

### Dorothy Weglend

That's right.

9. Nov 26, 2006

### AznBoi

would this be right??

For b) you need to find the work force of gravity.
So, W=(9.8m/s^2)cos180(3m)??

because the force of gravity acts downards and the displacement is upwards so it would be cos180 right?

10. Nov 26, 2006

### Dorothy Weglend

Yes, that's right.