1. The problem statement, all variables and given/known data A 265-kg load is lifted 24.0 m vertically with an acceleration =0.190 g by a single cable. Determine the work done by gravity on the load. 2. Relevant equations Force of Gravity = mg W = F * d * cos (theta) 3. The attempt at a solution I think I know why I did this incorrectly but I want to make sure. First attempt: Force gravity = (265 kg)(9.8 m/s^2) = 2.6 * 10^3 N. W = (2.6 x 10^3 N) (24.0 m) * cos (0°) W = 6.24 x 10^4 J. The correct answer is the same magnitude but the opposite sign. Is that because the angle should have been 180° because gravity always points down? The displacement is up so therefore the angle between the net force and the displacement would have been 180°, not 0°?