(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

A 265-kg load is lifted 24.0 m vertically with an acceleration =0.190 g by a single cable.

Determine the work done by gravity on the load.

2. Relevant equations

Force of Gravity = mg

W = F * d * cos (theta)

3. The attempt at a solution

I think I know why I did this incorrectly but I want to make sure.

First attempt: Force gravity = (265 kg)(9.8 m/s^2) = 2.6 * 10^3 N.

W = (2.6 x 10^3 N) (24.0 m) * cos (0°)

W = 6.24 x 10^4 J.

The correct answer is the same magnitude but the opposite sign. Is that because the angle should have been 180° because gravity always points down? The displacement is up so therefore the angle between the net force and the displacement would have been 180°, not 0°?

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# Work Done by Gravity

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