Work Done by Water on Skier: Solving a Physics Problem

AI Thread Summary
A physics problem involving a water skier moving at 14 m/s with a rope tension of 90 N at a 35-degree angle is discussed, focusing on calculating the work done by the water's resistive force over 50 meters. Participants emphasize the importance of understanding the force diagram, noting that the resistive force balances the x-component of the tension since the skier is not accelerating. The equation W = F * D is highlighted, with a suggestion to compute the tension's component in the direction of motion. The conversation also touches on the dynamics of collaboration and constructive feedback in problem-solving. Overall, the discussion centers on applying physics concepts to solve the given problem effectively.
soul5
Messages
63
Reaction score
0

Homework Statement


A water skier is moving at 14m/s. The rope makes a 35 degree angle with the centre line of the boat. If the tension in the rope is 90.0N, how much work does the resistive force of the water do on the skier while traveling 50 meters.


Homework Equations


W=FD



The Attempt at a Solution


I tried finding F in the x?
 
Physics news on Phys.org
I don't think you tried hard enough. Can you show us what you did? Since the skier is not accelerating the resistive force balances the x component of the tension force.
 
There is no acceleration so draw the force diagram. x-part of the tension is equal to the resistance.
 
silvashadow said:
There is no acceleration so draw the force diagram. x-part of the tension is equal to the resistance.

In what way does that differ from what I said? Or are you just reinforcing the point?
 
Dick said:
I don't think you tried hard enough. Can you show us what you did? Since the skier is not accelerating the resistive force balances the x component of the tension force.

lol what does that mean?
 
You quoted equations, I thought you knew how to use them. W=F*D where F is the component of the force in the direction of the displacement. Compute the component of the tension in the direction of motion, lol.
 
Dick said:
In what way does that differ from what I said? Or are you just reinforcing the point?

Sorry Dick, I guess second opinions are not welcome here.
 
Sorry, silvashadow. I always regret writing negative stuff like that. I know you were just trying to help.
 
Back
Top