Work Done Car Uphill PE and KE

  • Thread starter MMCS
  • Start date
  • #1
151
0
if a car of mass 980kg accelerates up an incline (10°to the horizontal) and increases its speed from 8.3m/s to 13.8m/s in 60m, both the air resistance and rolling resistance are taken as constant at 50N and 200N respectivelyfor the acceleration period described, determine work done

work done = Δkinetic energy + Potential energy

kinetic energy = 1/2 * mass * (v22-v12)
PE = mgh

work done = 1/2 * 980 * (13.82-8.32) + 980 * 9.81 * 60sin(10) + 50N + 200N = 161KJ

but I have the answer to be 175KJ
 

Answers and Replies

  • #2
tiny-tim
Science Advisor
Homework Helper
25,836
251
Hi MMCS! :smile:
… + 50N + 200N = 161KJ

Anything strike you as odd about those units? :wink:
 
  • #3
151
0
Ah of course, multiply these forces by the the distance to get units of Nm. Thanks tiny-tim!
 

Related Threads on Work Done Car Uphill PE and KE

  • Last Post
Replies
4
Views
3K
  • Last Post
Replies
17
Views
2K
  • Last Post
Replies
1
Views
6K
  • Last Post
Replies
13
Views
4K
  • Last Post
Replies
7
Views
1K
  • Last Post
Replies
3
Views
3K
Replies
5
Views
2K
  • Last Post
Replies
19
Views
303
  • Last Post
Replies
5
Views
2K
  • Last Post
Replies
3
Views
6K
Top