(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

Find the work done by the force field F(x,y) = (x+2y^2)j as an object moves once counterclockwise about the circle (x-2^2+y^2=1 by first evaluating the integral directly then use Green's Theorem and evaluate the double integral.

2. Relevant equations

W = F*D*cos(theta)

3. The attempt at a solution

My problem is not in getting the answer. I haven't gotten the final answer yet, but that's not the issue at hand.

My Calc teacher told me that it is NOT zero, and I am wondering why. If you move around in a circle, there is no displacement, so therefore, work should be equal to zero. So what is it that makes this case different from everything I did in Physics class?

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# Work Done in Circle - Why Not Zero? (Calc 3)

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