Work Done on 12kg Mass: 52N - 15N over 24m

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A force of 52 N is applied to a 12 kg mass with a sliding friction force of 15 N over a distance of 24 m. To calculate the work done in overcoming friction, the frictional force (15 N) should be multiplied by the displacement (24 m). This results in the work done by friction being 360 J. The net force of 37 N (52 N - 15 N) can be used to find the block's final kinetic energy but is not needed for calculating the work against friction. Therefore, the work done in overcoming friction is correctly calculated as 360 J.
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Homework Statement


A force of 52 N is applied to a 12 kg mass resting on a bench where the force of sliding friction is 15 N. The work done in overcoming friction while moving the object 24 m is


Homework Equations


w=fd


The Attempt at a Solution


could i just subtract 15N from 52N, then multiply that number by 24m to find the work??
 
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Why subtract? 52-15 would be the net force on the object, so if you plug that into W=Fd, you'd find the block's final kinetic energy. You want the work done by friction--which, because of the conservation of energy, is equal to the work done in overcoming friction.
 
dance_sg said:

Homework Statement


A force of 52 N is applied to a 12 kg mass resting on a bench where the force of sliding friction is 15 N. The work done in overcoming friction while moving the object 24 m is


Homework Equations


w=fd


The Attempt at a Solution


could i just subtract 15N from 52N, then multiply that number by 24m to find the work??
The work done in overcoming friction = frictional force X displacement.
 
so all i do is multiply 15N by 24m??
 
Yes, that's the work done by friction.
 

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