1. The problem statement, all variables and given/known data A man drags a sack of flour of mass 50kg at a constant speed up an inclined plane to a height of 5.0m. The plane makes an angle of 30 degrees with the horizontal, and has a constant frictonal force of 200N, which acts on the sack down the plane. Calculate the work the man has dne against the friction, and against gravity. 2. Relevant equations [tex]W=(F)(S)[/tex] (Where f=force and s=displacement) [tex]W=(F\cos\vartheta)(S)[/tex] **Also usage of SOHCAHTOA to solve the triangle. 3. The attempt at a solution Well, first I drew a triangle for the problem, and obtained that he travels a total of 10m going upward 30 degrees to the horizontal. Therefore, I solved it like this: Against friction, the force is 200N, so (200cos30)(10) = 1732J. Against gravity, the force is (50)(9.8) so (490cos30)(10)=4244J. **I am unclear overall if im doing this right, some help?