(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

A man drags a sack of flour of mass 50kg at a constant speed up an inclined plane to a height of 5.0m. The plane makes an angle of 30 degrees with the horizontal, and has a constant frictonal force of 200N, which acts on the sack down the plane. Calculate the work the man has dne against the friction, and against gravity.

2. Relevant equations

[tex]W=(F)(S)[/tex] (Where f=force and s=displacement)

[tex]W=(F\cos\vartheta)(S)[/tex]

**Also usage of SOHCAHTOA to solve the triangle.

3. The attempt at a solution

Well, first I drew a triangle for the problem, and obtained that he travels a total of 10m going upward 30 degrees to the horizontal.

Therefore, I solved it like this:

Against friction, the force is 200N, so (200cos30)(10) = 1732J.

Against gravity, the force is (50)(9.8) so (490cos30)(10)=4244J.

**I am unclear overall if im doing this right, some help?

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# Homework Help: Work, Energy and Power (Work Problem)

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