Work Energy Problem: Calculating Distance with Friction

AI Thread Summary
To solve the work-energy problem, the total work done on the crate is 73.3 J, and the horizontal force applied is 111 N. The coefficient of kinetic friction is 0.120, which affects the net force acting on the crate. The equation w = fd can be used to find the distance, where f is the net force after accounting for friction. Static friction is not relevant here since the crate is already in motion, and only kinetic friction should be considered.
Jtappan
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Homework Statement



Juana slides a crate along the floor of the moving van. The coefficient of kinetic friction between the crate and the van floor is 0.120. The crate has a mass of 59.1 kg and Juana pushes with a horizontal force of 111 N. If 73.3 J of total work are done on the crate, how far along the van floor does it move?

____J

Homework Equations



w=fd?

The Attempt at a Solution



How does static friction fit into this equation? I know this is a work problem but I am just confused as to how I put static friction into the equation.
 
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Its kinetic friction, not static since the crate is moving. You misread the question.
 

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