(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

A daredevil on a motorcycle leaves the end of a ramp with a speed of 39.0 m/s as in Figure P5.23. If his speed is 36.8 m/s when he reaches the peak of the path, what is the maximum height that he reaches? Ignore friction and air resistance.

3. The attempt at a solution

I figured I would start by finding the height when he is going off the ramp so I did this:

V^2=Vo^2-2g(Y-Yo)

39^2=0^2-2(9.80)(Y-Yo)

and wound up with

(Y-Yo)=-77.6 m

I'm not sure if I'm doing this correctly because I got a negative height. Should I just get rid of the negative sign and use this as my height?

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# Homework Help: Work/Energy Problem

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