Work Energy Theorem and Uniform Disc Problem

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theBEAST
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Homework Statement


Using work energy theorem, solve:
Diagram of a uniform disk of mass 20 kg at the end of a strut pivoted at the floor, angled 60 degrees from horizontal, with the disk against a vertical wall; labels include m=20 kg, omega=60 rad/s, mu=0.3, r=150 mm, theta=60 degrees, g=10 m/s^2, and an angle of 30 degrees.

The Attempt at a Solution


The actual answer (3.11s) is exactly half of my answer. Does anyone know what I did wrong?
Handwritten notes on lined paper: a free-body diagram of a disc on an incline with force equations for Fx and Fy, followed by work-energy and kinematics equations solving for theta = 186.59 rad and t = 6.225.
 
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Note that moment of inertia of a uniform disc about an axis through its centre and perpendicular to its plane is

[itex]\frac{1}{2}[/itex]MR[itex]^{2}[/itex].
 
grzz said:
Note that moment of inertia of a uniform disc about an axis through its centre and perpendicular to its plane is

[itex]\frac{1}{2}[/itex]MR[itex]^{2}[/itex].

Yup! That is what I used I believe.
 
theBEAST said:
Yup! That is what I used I believe.
There should be two factors of 1/2 - one from Iω2/2 for the KE and another from I=Mr2/2.