1. A rescue helicopter lifts a 90 kg person straight up by means of a cable. The person has an upward acceleration of 0.70 m/s2 and is lifted from rest through a distance of 10 m. What is the tension in the cable and how much work is done by the tension in the cable? Use the work-energy theorem to find the final speed of the person as well. 2. Work Energy theorem: Wnet = (1/2 mass velocity final^2) - (1/2 mass velocity initial^2) Tension: T = mass gravity 3. Tension: mass gravity T = 90 kg * 9.8 m/s^2 T = 882 N Which is wrong according to Webassign. WET = Delta K WET = (1/2 mass velocity final^2) - (1/2 mass velocity initial^2) Not sure how to go about solving this part. I guess the masses cancel, but what next?