A rope and pulley have negligible mass, and the pulley is frictionless. The coefficient of kinetic friction between the first block (8 kg) and the table is [tex]\mu[/tex]=.250. The blocks are released from rest. USE THE ENERGY METHODS TO CALCULATE THE SPEED OF BLOCK 2 (6 kg) after it has descended 1.5 meters. Basically there's a diagram: Block #1 rests on the table and is connected by a rope that goes through a pulley to block #2, which is hanging off the table. E = K + U W = FDcos[tex]\Theta[/tex] = [tex]\Delta[/tex]E [tex]\Sigma[/tex]F = F(Tens) - F(fric) Block #1: E-initial = PE = (6)(9.8)(1.5) E-final = KE = 1/2 (6) v^2 Block #2: E-initial = PE = ? E-final = KE = ? F = F(tens) - (8)(9.8)(.25) Whats the next step??