(adsbygoogle = window.adsbygoogle || []).push({}); A rope and pulley have negligible mass, and the pulley is frictionless. The coefficient of kinetic friction between the first block (8 kg) and the table is [tex]\mu[/tex]=.250. The blocks are released from rest. USE THE ENERGY METHODS TO CALCULATE THE SPEED OF BLOCK 2 (6 kg) after it has descended 1.5 meters.

Basically there's a diagram: Block #1 rests on the table and is connected by a rope that goes through a pulley to block #2, which is hanging off the table.

E = K + U

W = FDcos[tex]\Theta[/tex] = [tex]\Delta[/tex]E

[tex]\Sigma[/tex]F = F(Tens) - F(fric)

Block #1:

E-initial = PE = (6)(9.8)(1.5)

E-final = KE = 1/2 (6) v^2

Block #2:

E-initial = PE = ?

E-final = KE = ?

F = F(tens) - (8)(9.8)(.25)

Whats the next step??

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# Homework Help: Work-Energy with friction

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