This question is whooping me. I know I have the calculus part right I just dont know where to go from here? A particle moving along the x axis is acted upon by a single force F = F0e^(–kx), where F0 and k are constants. The particle is released from rest at x = 0. It will attain a maximum kinetic energy of F0/k F0/e^(k) kF0 1/2(kF0)^2 ke^(k)F0 So using the Work Kinetic Energy theorem W=Kf-Ki since x=0 then Kf=W W=integral(F = F0e^(–kx),x,0,xf) taking F0 out, since its a constant, and integrating the exponential function I get W=F0[-e^(-kxf)/k + 1/k] now what????