- #1
kiowaviator
- 3
- 0
This question is whooping me. I know I have the calculus part right I just don't know where to go from here?
A particle moving along the x-axis is acted upon by a single force F = F0e^(–kx), where F0 and k are constants. The particle is released from rest at x = 0. It will attain a maximum kinetic energy of
F0/k
F0/e^(k)
kF0
1/2(kF0)^2
ke^(k)F0
So using the Work Kinetic Energy theorem
W=Kf-Ki since x=0 then Kf=W
W=integral(F = F0e^(–kx),x,0,xf)
taking F0 out, since its a constant, and integrating the exponential function I get
W=F0[-e^(-kxf)/k + 1/k]
now what?
A particle moving along the x-axis is acted upon by a single force F = F0e^(–kx), where F0 and k are constants. The particle is released from rest at x = 0. It will attain a maximum kinetic energy of
F0/k
F0/e^(k)
kF0
1/2(kF0)^2
ke^(k)F0
So using the Work Kinetic Energy theorem
W=Kf-Ki since x=0 then Kf=W
W=integral(F = F0e^(–kx),x,0,xf)
taking F0 out, since its a constant, and integrating the exponential function I get
W=F0[-e^(-kxf)/k + 1/k]
now what?