Work needed to flip cone upside down.

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Given the cone, z^2=x^2+y^2 z<= 1 filled with water, find the work needed to flip the cone upside down.



W = Fd



Well, I figured I could integrate the force along the distance (0,1) by multiplying the distance from 0 times the cross section circle area times the density. That would give me the force of the cone, but then I would need to find the distance each infinitesimally small cross section would have to be displaced to flip the cone and I've gotten lost there.
 
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You'll find it a lot easier to use potential energy for this problem. Can you find the potential energy of the original cone and then the potential energy of the flipped cone?
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...

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