Work of a Line integral correction please

[Bibhatsu]

Homework Statement

Compute the Work of the following line integrals in the vector field \vec{V}=(2x^{2}-3y;4xy;3x^{2}z)

Homework Equations

For the following lines:

Curve1: \vec{r}(a)=(a,a,a^{2}); \ 0\le a \le 1

Curve2: \vec{r}(a)=(a,a^{2},a); \ 0\le a \le 1

The Attempt at a Solution

For the first Curve I got \frac{7}{6} and for the second one \frac{121}{60}.

Is this correct?Thank you in advance

Bibhatsu

 

[CompuChip]

I did the calculation quickly, but I got 3/2 for the first one.
Can you maybe show a little more work?

 

[SammyS]

I did the calculation quickly, but I got 3/2 for the first one.

I got 3/2 also.

 

[Bibhatsu]

Hey guys, so the second one is correct ? This is the integral I figured for the first one:

\int _{0}^{1} -3a+2a^{2}+4a^{3}+6a^{5}da=\frac{7}{6}Edit: there should be an integral symbol in front of the _{0}^{1}, seems it won't render. Sorry! Thanks for your feedbackBibhatsu

 

[SammyS]

4xy = 4a² when x=a and y=a.

The integral should be:

\int _{0}^{1} -3a+2a^{2}+4a^{2}+6a^{5}\,da

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[Bibhatsu]

Hello,I see my mistake.Thank you. Greetings

Bibhatsu

 

[Bibhatsu]

Hello,


I see my mistake.


Thank you.


Greetings

Bibhatsu