Work of a Particle in the XY Plane

AI Thread Summary
The discussion centers on calculating the work done by a force F = (2yi + 1.2x^2 j)N on a particle moving from the origin to the coordinates (5m, 5m) in the xy-plane. The integral approach to finding work involves partitioning the path into segments, specifically Woa and Wac. A key point of confusion is the assertion that the work done on segment OA is zero, despite the presence of a force in the x-direction. This raises questions about the nature of the force and the path taken, particularly regarding the locations of points A and C. Understanding the reasoning behind the zero work on segment OA is crucial for grasping the overall solution.
Redfire66
Messages
36
Reaction score
0

Homework Statement


A force acting on a particle moving in the xy-plane is F = (2yi + 1.2x^2 j)N. where x and y are in meters. The particle moves from the origin to a final position having coordinates x = 5m and y = 5m. Calculate the work done by F along OAC

Homework Equations


Integral of force by distance
W = ∫(Fxdx + Fydy)

The Attempt at a Solution


I have the answer. And I know what they did. But what I don't understand is how it makes sense.
The solution involves breaking up the integral into two partitions, Woa and Wac.
This is what I don't really understand - how is the work on OA zero? There is a force acting in the x direction and it moves from O to A. So by definition, since there is a force acting over a distance there should be work right? (Unless I'm not reading this properly)
 
Physics news on Phys.org
Where are points A and C?
 

Thread 'Errors and significant figures'

I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
View full post »
Thread 'A cylinder connected to a hanging mass'

Thread 'A cylinder connected to a hanging mass'

Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
View full post »

Similar threads

Particle moving from one potential to another
Replies
13
Views
1K
Particle's Motion in XY Coordinate System
Replies
19
Views
2K
Resistance force changing the velocity of an object
Replies
8
Views
1K
Calculate the work done in Rectangle?
Replies
2
Views
3K
Help calculating work in an xy plane
Replies
5
Views
4K
Problem Involving work, velocity, given Graph
Replies
1
Views
1K
Block on top of an inclined plane, with a rough surface, that moves with constant acceleration
Replies
41
Views
4K
Closest distance of approach between 2 charged particles
Replies
5
Views
1K
What should be the work done here?
Replies
9
Views
2K
How much work is done? (Frictionless plane, xy coodrinates)
Replies
3
Views
4K

Hot Threads

Recent Insights

Back
Top