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jj8890
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[SOLVED] Work on an object moving in a circle.
I have a question for a test review that has two people, a with a certain mass, let's say m_A and m_B riding on a spinning ferris wheel with a certain radius, let's say R, in carts opposite to one another. One (A) is originally at the bottom of the ferris wheel while the other (B) is at the top of the ferris wheel. As the wheel turns, B comes to the bottom while A arrives at the top. Neglect air resistance. I need to find the magnitude of the total work done on A and B moving from the bottom to top and top to bottom respectively.
I don't want to give the numbers because I want to work it out myself. I just need help figuring out how to set up the problem. I would appreciate any help.
The total work is the sum of the work done by all of the forces on the body, W total = F_net · ds.
I was thinking that the W_total on student A from bottom to top would be found by 2(Ma-Mb)gR but I am not sure that this looks right.
Wouldn't the Work done on student B by Ferris wheel is be 0 because the direction of motion is always perpendicular to force?
Homework Statement
I have a question for a test review that has two people, a with a certain mass, let's say m_A and m_B riding on a spinning ferris wheel with a certain radius, let's say R, in carts opposite to one another. One (A) is originally at the bottom of the ferris wheel while the other (B) is at the top of the ferris wheel. As the wheel turns, B comes to the bottom while A arrives at the top. Neglect air resistance. I need to find the magnitude of the total work done on A and B moving from the bottom to top and top to bottom respectively.
I don't want to give the numbers because I want to work it out myself. I just need help figuring out how to set up the problem. I would appreciate any help.
Homework Equations
The total work is the sum of the work done by all of the forces on the body, W total = F_net · ds.
The Attempt at a Solution
I was thinking that the W_total on student A from bottom to top would be found by 2(Ma-Mb)gR but I am not sure that this looks right.
Wouldn't the Work done on student B by Ferris wheel is be 0 because the direction of motion is always perpendicular to force?