Work Sleigh Problem: Calculating Horse Work & Power

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To calculate the work done by the horse pulling the sleigh, the formula for work (W = F × d) is used, where F is the force exerted by the horse and d is the distance traveled. Given the mass of the sleigh and the coefficient of kinetic friction, the force of friction can be calculated to determine the work done. For part B, power is calculated using the formula (Power = Work/Time), where the time is converted to seconds for accuracy. The discussion emphasizes understanding the relationship between force, work, and power in the context of the problem. This approach provides a clear method for solving similar physics problems involving work and power.
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A sleigh of mass 120.0kg is pulled by one horse at a constant velocity for a distance of .750 km on a level snowy surface. the coefficient of kinetic friction between the sleigh runners and the snow is 0.250. A) what is the work done by the horse? B) what power must the horse deliver to the sliegh for the trip to take 10.0 mins?

Could someone point me in the right direction on this one?
I am lost

Anyone that can help please let me know I also have some other problems
 
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OK, please post 'em separately and welcome to the Forums. What is the formula for work in terms of the force applied by the horse and the distance over which it acts? If the horse moves at constant speed, what must be its force against friction in light of Newton 1?
 
And for part B, remember that power is merely work/time
 

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