Work, Velocity, Friction, and Potential Engery with a sliding block

AI Thread Summary
The discussion centers on a physics problem involving a block sliding through various points with friction and height changes. The user has calculated the speeds at points B and C correctly but is struggling with determining if the block reaches point D and its speed there. They attempted to use kinematic equations to find the final velocity after accounting for friction but received an incorrect answer. Other participants suggest rechecking calculations without rounding errors, and the user considers discussing the issue with their teacher for clarification. The conversation highlights the importance of precise calculations in physics problems involving friction and energy.
Phoenixtears
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Homework Statement


In the figure below, a small block is sent through point A with a speed of 8.1 m/s. Its path is without friction until it reaches the section of length L = 12 m, where the coefficient of kinetic friction is 0.70. The indicated heights are h1 = 8.0 m and h2 = 1.1 m.
(Image Attached)

(a) What is the speed of the block at point B?
15 m/s
(b) What is the speed of the block at point C?
14.1 m/s
(c) Does the block reach point D?
---Select--- yes no
If so, what is its speed there and if not, how far through the section of friction does it travel?
in units of m/s


Homework Equations



Kinematics equations
Mu*N= Fkinetic

The Attempt at a Solution



Now, I've already finished a, b, c, I just need help with d. I first determined that all I had to do was set up a kinematics graph and use point C as my starting point. So, my inital velocity would be 14.1, my acceleration (which I got from using the second equation above, the normal force is equal to the weight for mg) is -6.86, and my delta-x is 12.

I realize that the picture does not depict L to be 12 exactly, but I see no other way to do this. Then, using the Vf^2=Vo^2 +2ax equation I solved for Vf. My answer was 5.84 m/s, however, this is incorrect. Could someone lead me to the right direction?

Thanks in advance!

~Phoenix
 

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Phoenixtears said:
Then, using the Vf^2=Vo^2 +2ax equation I solved for Vf. My answer was 5.84 m/s, however, this is incorrect.
Looks good to me.

(Perhaps it's a fluke in the online system. Try redoing your calculations without rounding off until the last step.)
 
Thanks for your response! At least I feel like I know what I'm doing... I'll redo it right now.
 
Hmm... turns out I didn't round anything off until the end. And still got the same answer. Perhaps I should merely confront my teacher tomorrow about the incident. Is there anything else I could possibly be doing wrong?
 
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