Worked gas prob with my anwer +correct answer

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SUMMARY

The discussion revolves around calculating the mass of NO2 formed in the reaction 2NO(g) + O2(g) → 2NO2(g) using the ideal gas law. The user initially calculated the change in pressure to find the moles of gas produced, resulting in 1.33 grams of NO2. However, the correct answer is 2.66 grams, indicating that the user must account for the stoichiometry of the reaction, which shows that two moles of NO produce two moles of NO2. The user misinterpreted the stoichiometric coefficients in the reaction.

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stoichiometric relationships

Homework Statement



hey guys just wondering if you could tell me where i went wrong
"One process related to formation of smog is:
2NO(g) + O2(g) 2NO2(g)
This reaction can be monitored in the laboratory by finding the total pressure of a mixture of the gases.

A bulb of volume 1.000 L is filled with a mixture of NO(g) and O2(g). The initial total pressure is 335 kPa at 26.4°C. After 6 hours the total pressure is 263 kPa. What mass of NO2(g) in grams has been formed? "

PV=nRT
P=335Kpa-263Kpa=72Kpa
R=8.314
v=1
t=299.4K

n=PV/RT=72/(8.314*299.4)=0.0289
Therefore mass =moles*molermass=0.0289*46.01=1.33grams HOWEVER answer is 2.66grams? therefore i should mulitple my answer by 2, but Y?
anyhelp would be apprecitated




Homework Equations





The Attempt at a Solution

 
Last edited:
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If I understand what you did correctly, 72 kPa is amount of oxygen that reacted - take a look at the reaction equation now...
 

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