X and y components in force problem

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To solve the problem of a 10 kg sled being pulled at an angle of 35 degrees east of north by a 100 N force and a 150 N force directed due east, the x and y components of the angled force need to be calculated. The tension force (Ft) of 100 N can be broken down into its east and north components using trigonometric functions. The east component is found using cos(180-35), while the north component is calculated using sin(35). Additionally, a friction force of 50 N must be considered to determine the sled's acceleration. The final calculation will yield both the magnitude and direction of the sled's acceleration.
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The problem is:
A 10 kg sled is pulled at an angle of 35 o east of north by a force of 100 N and with a force of 150 N directed due east. A friction force of 50 N acts as well. What is the acceleration (both magnitude and direction of the sled.

My question - could someone help me properly draw out the x and y components of the angled Force ? Thanks in advance
 
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The Tension Force (Ft) is in the direction of the rope and you are told that the total Ft=100 N

So you want to figure out the east and north components of this force. Draw a triangle with the hypotenuse as Ft=100 N

To get the east component, you want to take cos(180-35) because cos(x)=adjacent(east)/hypotenuse , now solve for the adjacent(east) component. You can do the same to get the north component, but by using sin(x)=opposite(north)/hypotenuse
 
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